Recent content by mje537

y=(5.9)(3.9)+1/2(1.3)(3.92) y=23.01+9.8865 y=32.896

im sorry but phyiscs is my most complicated subject and i don't know wat you mean by a. is it the acceleration.

to find the time i used. y=2V0Sindeta/g y=2(5.9)(sin13)/9.81 y=2.7 then i used ur equation. x=V0x t + ½ ax t2 x=(5.9)(2.7)+1/2(9.8)(2.7)2 x=15.93+35.721 x=51.651 so did i do anythin wrong.?

well i tried the time equation. t=2V0Sindeta/g and then i used the displacement formula y= V0t + 1/2gt2 but they told me it was wrong. i don't want the answer i just want to know the concept of how to get the answer. wat i do wrong.?

vertical displacement!? help anyone. =] i have no idea wat to do!?? In a scene in an action movie, a stunt man jumps from the top of one building to the top of another building 3.9 m away. After a running start, he leaps at an angle of 13◦ with respect to the flat roof while traveling at...