Recent content by mnech

  1. M

    What are all the functions that satisfy (Calculus II)

    However, I am unsure how a -1 will give me more answers. when taking the square root of both sides, it would become: \frac{|f(x)|}{|\int f(x) dx|} = (negative?)1 sorry, but can you elaborate, by including -e^x in the answer (from the absolute value another step or two down), how is that...
  2. M

    What are all the functions that satisfy (Calculus II)

    The problem: (\int f(x)dx)(\int \frac{1}{f(x)} dx) = -1 solve for f(x) The attempt at a solution divide both sides by integral(f(x)dx): \int \frac{1}{f(x)} dx = \frac{-1}{\int f(x)dx} took derivative of both sides: \frac{1}{f(x)} = \frac{f(x)}{(\int f(x) dx)^2} multiplied both sides by f(x)...
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