Hi, thanks. I have calculated the net force on both axes and it results:
##F_{x}=-Kx## ## \vec i## and ##F_{y}=mg-Ky## ##\vec j##. Since in ##(a)## the impulse is horizontal, the mass will remain on the same coordinate ##y=L_{0}## because ##F_{y}=mg-Ky=mg-KL_{0}=0##. Thus, during the motion...
Homework Statement
A pointlike body of mass ##m=100## ##g## is attached to the extremity of an ideal spring, whose constant is ##K## and its length at relaxed position is negligible. The other extremity of the spring is attached to the fixed point ##O##.
At first the body mass, on which the...