Roger that, a careless mistake. Thanks. I appreciate all of your time and attention. I'm now able to follow the effort to standardize the kilogram in terms of Avogadro's number and Planck's constant.
Dale: I don't see any mass squared in my above. That said, I see my mistake: I needed to have divided 12 not multiplied by 12. (whoops!) Thanks for the help.
P(mass) = 1.67262e-24g x 6 protons = 1.0035738e-23 g
N(mass) = 1.67492e-24g x 6 neutrons = 1.0049571e-23g
Total C(mass) = 2.00853e-23g
2.00853e-23g x 12g(C) = 2.410236e-22g (Mass of 12 grams of C-12)
Robphy: Thanks so much for providing the link to R.A. Millikan's original work. It will take time to plow through. Avogadro's constant should equal roughly the mass of the number of protons and neutrons in 12 grams of C-12, yet it doesn't add up. Any idea why not? (Note: I assume neutron mass...
Robphy: How did Millikan know what a "mol of electrons" was before he had quantified Avogadro's number? It is said he determined Avogadro's number by dividing a mol of electrons by the charge of an electron to get 6.022e23. Please tell me what number is equal to a mol of electrons?
My question is being misunderstood (my fault). How can Milikan talk about a MOL of electrons before the mol had been quantified at 6.022 e23? Put another way, what was Milikan's understanding of how many electrons were in a mol of electrons?
Frustratingly, everything I read about deriving Avogadro's number uses the word "mole" somewhere in the explanation. Per Scientific American, for example, Robert Millikan divided the charge on a mole of electrons by the charge on a single electron to obtain a value of Avogadro’s number of...
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