Recent content by mopar969

Ooops I forgot to type in the option for c. After reading the link above provided by a PF member It says that options a and b can both be used. Therefore the answer to this question is then D. Is this correct.

A particular temperature interval, as opposed to a particular temperature value is written (a) C°, (b) °C, (c) degrees celsius minus degrees celsius (d) it makes no difference. I am unsure as to what the question is asking.

Thanks again for the help.

Temperature is associated with molecular (a) rotational energy, (b) random translational energy, (c) vibrational energy, (d) all of the preceding. I am pretty sure that the answer is D all of the preceeding but I just wanted to check.

Thanks.

Only one answer is correct so I think the best answer is kinetic energy which is option B. What do you think, am I right?

When a substance undergoes a phase change, the added heat changes (a) the temperature, (b) the kinetic energy, (c) the potential energy, (d) the mass of the substance. I believe the answer is kinetic energy because the molecules move faster.

Thanks

Largest Unit of Heat Energy? Which of the following is the largest unit of heat energy: (a) calorie, (b) Btu, (c) joule, or (d) kilojoule. I narrowed it down to kilojoule or btu. I think it is btu.

Thanks so so much for the help gneill you are a life saver. By the way I am done now right? If you have time could you give a recap. Thanks

I thought that the electric field for that part was just 5 (r^4 - r sub two to the fourth) c/m^4 all over 4 epsilon zero r^2. Since it is not what is this then?

One more thing what does the electric field in post 65 represent and for what region?

So for my r I should use 0.002 m and for r2 I should use 0.0012m and get a Q of 2.19 x10^ -10 couloumb add that to 7.4 x 10^-6 couloumbs and get 7.4 x10^-6 couloumbs. I then plug this into the electric field equation and got 6.65x10^4 nm^2/c all over r^2. Is this correct? Also this is for r >...

So for the third region it is 5 (r^4 - r sub 2 to the fourth) c/m^4 all over 4 epsilon zero r^2 the fourth region is (3.69 x 10^4 Nm^2 /c all over r^2 + 5 pi (r^4 - r sub 2 to the fourth) c/m^4) all over 4 pi epsilon zero r^2 Does this reduce any further?

So for r in the conductor E = 0 r1 < r < r2 E = 3.69 x10^4 Nm^2 /C all oiver r^2 r2 < r < r3 E = 5 (r^4 - r sub zero to the fourth) c/m^4 all over 4 epsilon zero r^2 r > r3 E = the previous electric field plus th electric field of r1 < r < r2. Are all these correct and is this finally the...