This was all the data given. I think I have it:
I found the acceleration using the kinematics equation
∆d = t*V1 + 1/2*a*t^2
in which ∆d = 1.2, V1 = 0, and t = 0.300s
1.2m = 0.300s*(0 m/s) + 1/2a(0.300)^2
then the a turns out to be 26.666 m/s
Then I broke the acceleration into...
Hello,
Homework Statement
You throw a 0.500 kg rock underhand, as shown in the diagram. The rock starts at rest from the lowest point moving at an angle of 40° above the horizontal, and leaves your hand 0.300 s later having traveled 1.20 m. What is the average force that you exert on the...