Recent content by Morphheus

I don't really get the "using the original equation" part. To solve such an equation, I would guess that q(t) = Ae^αt, then solve for alpha (which would give me α = ±√(something), and would finally re-plug these alphas using the superposition principle in q(t) My final answer would be...

Yep.

Properly think about it: The mass is hanging from the spring. I assume that when it is observed, it can be considered at rest. If it's at rest, there are only two forces acting on the mass: gravity and the spring force. Since the mass is at rest, all forces must cancel each other. . Since both...

The height of the plane is changing. It's speed is of 180 m/s at 15 degrees below the horizontal. It is therefore losing altitude. This is a 2d problem: you could set the x-axis pointing to the north, and the y-axis being the height. Draw a diagram: it will drastically help you understand...

F=ma In this case, the acceleration is not g, but something else. If you consider the acceleration to be constant, you can easily determine the acceleration from the time and speed given in the initial conditions

Homework Statement Solve the following differential equation for q(t) (position): q''-qω^2 = C, where C is a time-independent value (basically a constant)The Attempt at a Solution This equation is not homogeneous, therefore it must be non-homogeneous. However, in every definition of...