I basically found an area of water at the 12" depth and, found its mass and used that mass in the centripital force eq. Used my tan. velocity of 3.7 ft/s at the 24" radius and solved for centripital force. And I did not consider varaible water level height because I am looking for a ball park...
I have a 36" OD aluminum drum within another 48" OD aluminum drum creating 6” channel between the two diameters. The total height of the drum assembly is 16” This design project that I am working on requires me to fill this channel up with 12” of water which equates to about 342.5 lbs of water...