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mpf

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My way of doing it: I found the ambient pressure at a 12in depth which was 0.43363psi. From the f=pa eq. I then picked an area at the bottom of the drum which was 6” wide (channel width) x 1” giving me an area of 6 in^2. Took the f=pa eq. and multiplied it by the ambient pressure at 12” and got 2.60178 lbs. Plugged that into the f=ma eq. to get my weight given that area and got .0808lbs. Put that bad boy into the centripetal force eq. given my tan. Velocity which is 3.7483 ft/s and the radius which is 2ft and got .5674lbs of force at any location around the outside of the drum at a 12” depth. I know the load is a distributed load so you can solve with an integral for the whole drum wall or use a finite elemental analysis program to solve it but I tried to cut corners and get a ball part estimate. Can someone either validate this or tell me I’m way wrong and help me out. Thanks much