Recent content by mpmor1

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    Centripetal Motion along the horizontal with an angle

    That doesn't yield the correct answer online
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    Centripetal Motion along the horizontal with an angle

    If the mass of the stone is .2kg then the weight is 1.962N; this would make the horizontal component equal to that divided by the tangent of the angle, 25.
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    Centripetal Motion along the horizontal with an angle

    So if the horizontal component is the centripetal Force, that being 4.2075N, then this can simply be plugged into the equation V= sqrt(Fr/m)?
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    Centripetal Motion along the horizontal with an angle

    The two forces acting on the stone are its weight, pointing straight down, and the unknown centripetal force which can be seen as the tension in the string
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    Centripetal Motion along the horizontal with an angle

    if the total force is broken into its horizontal and vertical components, can its force of weight (1.962N) be treated as the vertical component?
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    Centripetal Motion along the horizontal with an angle

    Homework Statement A 0.20 kg stone attached to a 0.8 m long string is rotated in a horizontal plane. The string makes an angle of 25° with the horizontal. Determine the speed of the stone.Homework Equations V= √(Fr/m)The Attempt at a Solution find the vertical component, call it y, then say...