Recent content by Mr_Pu

So if I understand correctly, I should write the Coloumbs law, for the charge distributed on a sphere and then limit that to r=0?

Can you please show your work, I'm kind of lost here.

E dS = de/ε --> E ∫2πrdr = ∫(B/r ⋅ 4πr^2 dr)/ε --> Eπr^2 = 2πB(r^2 - R^2) --> E = 2B(r^2 - R^2)/r^2

When I compute the integral for electric field inside a sphere ∫E dS = ∫ de / ε I get that E = 2B(r^2 - R^2)/r^2 which doesn't make any sense to me, since when R = 0, E is just 2B

I think it doesn't.

However, the thing that troubles me, is that in the middle the density of charge limits to infinity and I'm not sure how to build out a formula for that.

I have already calculated full charge inside the sphere: e = ∫ρ dV = 2πBr^2 And I know that electric potential on the edge of the sphere is: U = e/ 4πεr The idea is that I calculate work by the change of electric potential energy, but to do that, I have to calculate electric potential energy in...