Thanks for the pointer. I guess i didn't subtract the lower limit from the the upper limit
[325.2692 / (2π x 529)] x [ intergral with upper limit] - [ intergral with lower limit]
31.83 x (2.8345 - 0.3071)
= 80.45
Thats it, isn't it?
Thanx gneill
Thanks gneill
Here it is:
[V2 / (2πR)] x [ ½ (θ - (½ sin 2(θ)))]
[325.2692 / (2π x 529)] x [ ½ (5π/3 - (½ sin 2(5π/3)))]
31.83 x [ ½ (5.236 -( - 0.433))]
31.83 x 2.8345
90.2
Hi guys
I'm getting same as this but if I multiply with 31.83 that I am getting from (3.0086 x 10^-4) * 325.32^2
My answer is 89.9. Just wondering why my answer is off.
Please help
Thanks
Homework Statement
For a lossless line:
The characteristic impedance is given by Zo=sqrt(L/C)
and the velocity of propagation by Vp =1/(sqrt(L*C))
where L and C are, respectively, the line's inductance and capacitance per metre length.
A transmission line is formed by two identical parallel...
Converting Celsius to Kelvin
25degrees = 298.15 K
Plugging numbers into equation
Rn = (38.15 x 10^-6)^2 / (4 x (1.38 x 10^-23) x 298.15 x 1000000)
= 88433.17
Rn = 88.4 kOhms
Homework Statement
A simplified model of ADC noise refers the noise to a noisy source resistance Rn while assuming the rest of the signal path to be noiseless. Figure 3 represents a particular 18-bit ADC that has a 10 V input voltage range. The ADC has a bandwidth of 1 MHz.
Calculate the...
Is it correct to then say
Reflected = Rsecondary + (Rprimary / n^2)
Where n = (N1 / N2)
Which gives me RS = (0.007 - (0.010 / n^2)
Problem is I've failed to lose n^2 so I'm left with numerals only