Recent content by mrfunkyg

Thank you so much!

Hello Fzero thank you for the reply. f'(x)=x^2-2x=0 f'(0)=(0)^2-2(0)=0 (0,0) f'(2)=(2)^4-2(4)=0 (2,0)

Homework Statement Determine the points at which the graph of the function has a horizontal tangent f(x)=(x^2)/(x-1) Homework Equations The Attempt at a Solution f'(x)= ((x-1)(2x)-(x^2)(1))/((x-1)^2) ((2x^2)-2x-x^2))/(x-1)^2 f'(x)= ((x^2)-2x))/((x-1)^2) third step I set to 0 I...