Recent content by mshah3

negative x

alright, so how would i get to the etherm of the floor?

or wait no ... Fd

well i meant change in distance work = mgdetlar

oh ok that makes sense so Wfric = mct - mgh then would the etherm for floor be zero?

-Fd ?

well the block is moving to the right and the work by floor is moving upward making it perpendicular to motion (honestly, part b and c are the ones I am very unsure about) thank you

Homework Statement You push a block of lead across the floor, applying a horizontal force of 9 N. The block moves at a constant speed. The mass of the block is 1.5 kg and the heat capacity of lead is 130 J/(kg K). After pushing the block a distance of 20 m, you measure its temperature and find...

ok...well 120 didnt work so 60 is my best guess now any help for tension force or acceleration? the force isn't simply mass times 9.8 is it? or is it stiffness times stretch?

yeah that might make more sense because i submitted 120.8888 N/m and it was incrrect. so the correct k = 60.4444 ?

oh ok so this is the calculation i did, let me know if its correct(i only have one submission left): mgh=(ks^2)/2 (80)(9.8)(34) = (k)(21^2) / 2 k = 120.8888 N/m *also, any ideas for tension force or acceleration? *i tried Ft=kx = 392N and acceleration = change in...

never mind i figured out to use E/T = E/T just wasnt thinkin thanks

ok awesome. i got a final value of 4669.5675 J can u confirm this?

delta t for a = 24-4 = 20 delta t for b = 27-4 = 23 correct? so how do i use a ratio to get to the energy?

i just submitted that was incorrect