Recent content by Mstf_akkoc

Actualy is not true. I have done a misteke when calculete the [tan(x^2)]' 2xdx=cos^2(x^2)dm is true if I find a solution with this I ll write.

I think I have a solution. I hope it was not so late :). tan(x^2)=m dx=cos(x^2)dm integral [sin(x^2)] = integral [mdm/(m^2+1)] m^2+1=a and 2mdm=da ... integral [sin(x^2)] = 0.5*ln[(tan(x^2))^2+1]+c