Recent content by mtxop2

Damn I'm so sorry I misled you, I've been working on these all day and well you know how that goes. What I meant to say was product rule, where f(x) = e^(-1/2x) and g(x) = [c1cosx + c2sinx]

Homework Statement 4y" + 4y' + 5y = 0 y(0) = 3 y'(0) = 1 Homework Equations yh = e^ax(c1cosbx + c2sinbx) The Attempt at a Solution For the roots I got -1/2 + i and -1/2 - i so my a = -1/2 and b = 1 then I have to differentiate yh = e^(-1/2x)[c1cosx + c2sinx] this is where I get this...