Recent content by Muteb
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How Much Force Does a Horse Need to Pull a Sleigh?
Thanks for your help I don't know about it but could you tell me- Muteb
- Post #7
- Forum: Introductory Physics Homework Help
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Calculating Magnitude of Acceleration for 3.0 kg Mass w/ 2 Forces
but you forget to divide the Fy by Mass that -7.06/3 to get the ay that is -2.35 -------------------------------------------------------------------------------- a=((1.75^2) +(-2.35^2))^1/2 =2.93m/s^2- Muteb
- Post #6
- Forum: Introductory Physics Homework Help
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How Much Force Does a Horse Need to Pull a Sleigh?
Ft=375 + 382 Ft=757N i that right- Muteb
- Post #5
- Forum: Introductory Physics Homework Help
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Calculating Magnitude of Acceleration for 3.0 kg Mass w/ 2 Forces
a=((1.75^2) +(-7.06^2))^1/2 =7.28m/s^2 how about it now- Muteb
- Post #5
- Forum: Introductory Physics Homework Help
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How Much Force Does a Horse Need to Pull a Sleigh?
I think that Ft=375 + 382 Ft=757N But do you think the force (757N) can move the sleigh ( 2499N)?- Muteb
- Post #3
- Forum: Introductory Physics Homework Help
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Calculating Magnitude of Acceleration for 3.0 kg Mass w/ 2 Forces
Fx=ma 9cos0-8cos62=3a a=1.7m/^2 Fy=ma 9sin0-8sin62=ma ay= 1.97 a=(1.2^2 + 1.97^2)^1/2 a=2.30 m/s^2 is it right now and thanks for your help- Muteb
- Post #3
- Forum: Introductory Physics Homework Help
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How Much Force Does a Horse Need to Pull a Sleigh?
A hors og mass 509 KG Pulls a sleigh of mass 255 KG and both horse and sleigh accelerate 0.5 m/s^2. the coefficient of friction for the sleigh is 0.150 as it moves over the snow. Find the horizontal force that the horse must exert on the sleigh. Remember sleighs have two identical blades on the...- Muteb
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- Force Horizontal Horizontal force
- Replies: 7
- Forum: Introductory Physics Homework Help
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Calculating Magnitude of Acceleration for 3.0 kg Mass w/ 2 Forces
Only two foces act on a 3.0 kg mass.? Only two foces act on a 3.0 kg mass. One of the forces is 9.0 N east, and the other is 8.0 N in the direction of 62.0 north of wet. What i the magnitude of the acceleration of the mass? The mass has only TWO forces acting on it. No gravity. Not resting on...- Muteb
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- Forces
- Replies: 6
- Forum: Introductory Physics Homework Help
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How Does Thrust Affect a Satellite's Orbit?
A satellite of mass 59.0 Kg is being pulled out of orbit by 450.0? 1- A satellite of mass 59.0 Kg is being pulled out of orbit by 450.0 Netwons of gravity. Small thrusters are used to maneuver the satellite back to its orbite. a)What thrust would cause the satellite to move with a constant...- Muteb
- Thread
- Replies: 2
- Forum: Introductory Physics Homework Help
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What is the acceleration of the elevator?
I think this is ok now isn't it? F=4.8N F=ma 4.8kg*m/s^2=4kg*a a=1.2m/s^2 [u- Muteb
- Post #3
- Forum: Introductory Physics Homework Help
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Calculating Acceleration of an Elevator with a Suspended Object: Explained
Yes because the acceleration of the spring should be the same with the elevator. is the direction right that the acceleration is +1.2 m/s^2 that means that the elevator accelerates up?- Muteb
- Post #10
- Forum: Introductory Physics Homework Help
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Calculating Acceleration of an Elevator with a Suspended Object: Explained
I am really confused. 44-(4X9.8)= 4 X a a= 1.2 m/s^2 now I think that right because as you said the elevator has acceleration as the spring.- Muteb
- Post #8
- Forum: Introductory Physics Homework Help
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Calculating Acceleration of an Elevator with a Suspended Object: Explained
I think that was not right. because I am asked to find the elevator's acceleration. Mass of elevator is 44N / 9.8 = 4.5 44 N - (4.0 kg X 9.8) = a X 4.5 a = -1.1 m/s^2- Muteb
- Post #6
- Forum: Introductory Physics Homework Help
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This problem i have been trying to solve it for more than hours but i could not.
If I said that N=w because the ball is not moving. still I could not solve it because I need to know more information which let me to be able to solve it because I have two unknewn variables that are W and N- Muteb
- Post #7
- Forum: Introductory Physics Homework Help
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Calculating Acceleration of an Elevator with a Suspended Object: Explained
I can understand that 44 N - (4.0 kg X 9.8) = a X4 a= 1.2 m/s^2 is it ok now- Muteb
- Post #4
- Forum: Introductory Physics Homework Help