Recent content by mybrainhurts1

limx->o h^2/2h - limx->0 h/2h + limx->0 sinh/2h, but where do I go from here.

You're very helpful.

Yes, should be lim y->0 (sin3ycot5y)/ycot4y So for the first problem-- (h^2/1)-(h/2)+sinh/h= (0^2/1)-(0/2)+1=1...?

Can anyone help me with these two limit problems... solve: lim h->o (h^2-h+sinh)/2h and lim y->0 (sin3cot5y)/ycot4y I know lim x->0 sinx/x=1, but I can't figure out how to get these two into that format.