Recent content by N_Spears

um, so its area is 2bdy :| Sorry but what is this? Did you mean d\Phi?

According to my textbook, your formula and mine are the same :D @kuruman: uhm, so it looks like electromagnetic induction of the current flows into the wire affect 2 points in the loop whose distance will be r - b and r + b. And if the thickness of the line is very small so its area will be...

We have \Phi = BS\cos\alpha, but this formula just can be used when the magnetic field is uniform :|, I wonder if there is another formula :-<

Sorry, you're right. I've just revised my lesson. So, the current appears in the rectangular loop because the magnetic field is changing as the the rectangular loop is moving away from the wire. Please give me the next question, I promise that I will check my book before giving the answer :)

judging from what I've learned, current cannot appear in the rectangular but magnetic flux. And if it does, it will come from the straight conducting wire for sure, this happen because of the current flows into this wire. I was really confused about this question, I think there must be a...

Hix, this question isn't my homework, it's included in MEXT scholarship test. I have checked all the formula that I've known but none of them can solve this question. I suspect that our curriculum doesn't contain the right one. I live in Viet Nam. Can you help me?:(

1. The problem statement A current I passes through a straight conducting wire located within this page. Rectangular circuit ABCD on the page is moving away from the straight conducting wire with speed v, while side AB remains parallel with the current I. The length of side AB is 2a, and the...