Recent content by nae99

If f(x)= 2x+5, g(x)=0.5 and h(x)=3-1 find: fg(x), gf(x), fh(3) fg(x) fg(x)= 2(0.5x)+5 fg(x)= x+5 gf(x)= 0.5(2x+5) = x+2.5 fh(3) fh (x) =2(3-1)+5 = 6-2+5 = 4+5 this last part of the question been puzzling me... could I get a little...

Homework Statement find the equation of the straight line which is parallel to the line 3y+4x=6 and passes through the point F (1,7) Homework Equations The Attempt at a Solution 3y= -4x + 6 y= -4/3x + 2 im not sure what I am doing...im i on the right track

honestly i have no idea what is slope intercept :confused:

-3y=-5x+6 -3(4)=-5(-3) + 6 -12=15+6 -12=21 should it be done like that

Homework Statement find the equation of the straight line which is perpendicular to the line 5x-3y-6=0 and passes through the point (-3,4) Homework Equations The Attempt at a Solution -3y=-5x+6 where do i go from there

ok i gave up because i have no idea what i am doing...i don't know how to do it.

:rolleyes::confused: is it; d= a1 + 7d

i did just the bacis maths before and now I'm doing a precalculus course.

if u said u used up tow sheets of paper and still can't solve it, how am i going to and i hardly know what to do.

no, i do not know how to write it without using the term a_6 this how i would write it: a_1+a_2+a_3+a_4+a_5+a_6+a_7+a_8=56

a6 = 4*a1 + a2 * a1 + a2 + a3 i actually don't know what I am doing

oh ok a6 = 4*a2*a3

a1 + a2 + a3 + a4 + a5 + a6 + a7 + a8 = 56

a6 = 4xa2xa3

ar^7 = 56