How to Find the Equation of a Perpendicular Line?

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Homework Help Overview

The problem involves finding the equation of a straight line that is perpendicular to a given line, specifically 5x - 3y - 6 = 0, and passes through the point (-3, 4). The context is within the subject area of algebra, focusing on linear equations and their properties.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss converting the given line's equation into slope-intercept form to identify the slope. There are questions about the relationship between the slopes of perpendicular lines and how to apply this to find the slope of the desired line. Some participants express confusion about the concept of slope-intercept form and its application.

Discussion Status

There is ongoing exploration of the problem, with some participants offering guidance on necessary steps, such as reformulating the equation and understanding slope. However, there is a lack of consensus on the understanding of slope and its implications for solving the problem.

Contextual Notes

Some participants indicate that the original poster may not have a clear understanding of slope, which could hinder their ability to solve the problem. There are references to consulting textbooks for definitions and relationships related to slopes of lines.

nae99
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Homework Statement



find the equation of the straight line which is perpendicular to the line 5x-3y-6=0 and passes through the point (-3,4)

Homework Equations





The Attempt at a Solution


-3y=-5x+6

where do i go from there
 
Last edited:
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Finish putting the equation for the line into slope-intercept form, so that you can read what the slope is. What is the relationship between the slopes of two perpendicular lines? You can use that to find the slope of the line you are seeking. You are given a point which this new line must pass through, so you can get its equation from the point-slope form for a line.
 
dynamicsolo said:
Finish putting the equation for the line into slope-intercept form, so that you can read what the slope is. What is the relationship between the slopes of two perpendicular lines? You can use that to find the slope of the line you are seeking. You are given a point which this new line must pass through, so you can get its equation from the point-slope form for a line.

-3y=-5x+6

-3(4)=-5(-3) + 6
-12=15+6
-12=21

should it be done like that
 
If you're getting -12 = 21 , then that probably isn't what you need to do... You don't want to put ( -3, -4 ) into the original line's equation, because that point is not on the line you were given.

What is the slope-intercept form for -3y = -5x + 6 ? (What do you still need to do?)

Once you've done that, what does the equation tell you about the slope of this line you were given?
 
dynamicsolo said:
If you're getting -12 = 21 , then that probably isn't what you need to do... You don't want to put ( -3, -4 ) into the original line's equation, because that point is not on the line you were given.

What is the slope-intercept form for -3y = -5x + 6 ? (What do you still need to do?)

Once you've done that, what does the equation tell you about the slope of this line you were given?

honestly i have no idea what is slope intercept :confused:
 
nae99 said:
honestly i have no idea what is slope intercept :confused:

Then this problem is probably too advanced for you.
 
nae99 said:
honestly i have no idea what is slope intercept :confused:

1] Reformulate the equation in the form of y=mx+b.
2] Do you know how to calculate the slope of a line? Rise over run?
 
Last edited:
nae99 said:
honestly i have no idea what is slope intercept :confused:
Do you know what is meant by the slope of a line? If not, then, as phinds says, you shouldn't be attempting a problem like this. If it hs been given as coursework, then you should consult your textbook for the definition of "slope" and how the slopes of perpendicular lines are related.
 
i suggest use y=mx+c...frst find the slope of the equation..n use y1-y2/x2-x2=...
 
  • #10
apit3g said:
i suggest use y=mx+c...frst find the slope of the equation..n use y1-y2/x2-x2=...
Your expression needs parentheses. If a line contains the points (x1, y1) and (x2, y2), then the slope m is given by m = (y2 - y1)/(x2 - xSUB]1[/SUB])

The expression you wrote would be interpreted to mean
y_1 - \frac{y_2}{x_2} - x_1
but that's not what you meant.
 

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