Recent content by nafunkiii

Another explation to the problem that leads to the right answer assume car in 1 ,goat in other 2.. the man picks door 1 (host opens 2,3) TWO CASES. mans picks door 2 and host opens three and the other way round.. so in 2 cases out of 4 the man will win the car.. so equal probability

This is my Doubt. Suppose door 1 is picked. and the player always switches. There is a probability of 1/3 that the car is behind either doors. so if car is behind 1, host can open door 2 or 3 with probability of 1/2. so switching results in loss of 1/3 (1/6+1/6). so if car is...