Recent content by Naincy

ok. figured out the mistake. :) The final answer is: x(t) = $$\frac{125+3t}{5} + \frac{c}{({125+3t})^{2/3}}$$ I think this is correct. yeah ?

Did I get the integrating factor right ?

Integrating factor,here, is: (125+3t)^(2/3)

okay! right. So , i solved this linear first order differential equation and i got x(t) = $$\frac{125+3t}{2}\left[1+c({125+3t})^{-5/3}\right]$$ Can you just check if it's correct? Thanx. :)

Hi. Thanx No, it is actually 2x and not 2t in the numerator. It is a function in two variables x and t. I need to integrate it with respect to t. Note that x cannot be considered a constant here. so , it becomes integration of a function in two variables. i don't know how to start with it. any...

Hi How do you calculate the following indefinite integral: $$\int \frac{2x}{125+3t} dt$$ a step by step solution would be appreciated