Recent content by NaS4
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Using Complex Impedances in these RLC Circuit Calculations
Master1022 I got nothing but respect for you man. Really makes me happy to see people like you helping out people like me- NaS4
- Post #36
- Forum: Engineering and Comp Sci Homework Help
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Using Complex Impedances in these RLC Circuit Calculations
Yeah the w = 2(pi)f but since the question tells us that w is 200- NaS4
- Post #34
- Forum: Engineering and Comp Sci Homework Help
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Using Complex Impedances in these RLC Circuit Calculations
Thx man. I’ll look up dimensional analysis- NaS4
- Post #30
- Forum: Engineering and Comp Sci Homework Help
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Using Complex Impedances in these RLC Circuit Calculations
Master thanks a lot for the help man. You really are a lifesaver- NaS4
- Post #28
- Forum: Engineering and Comp Sci Homework Help
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Using Complex Impedances in these RLC Circuit Calculations
That 11.5k V sounds abit to high 😅- NaS4
- Post #25
- Forum: Engineering and Comp Sci Homework Help
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Using Complex Impedances in these RLC Circuit Calculations
@Master1022 So I've done most of the tasks now. But I'm abit unsure of task c) ii)- NaS4
- Post #24
- Forum: Engineering and Comp Sci Homework Help
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Using Complex Impedances in these RLC Circuit Calculations
Ok I’m lost now. How did you get (1 - w^2LC)- NaS4
- Post #22
- Forum: Engineering and Comp Sci Homework Help
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Using Complex Impedances in these RLC Circuit Calculations
@Master1022 How does this solution look?- NaS4
- Post #20
- Forum: Engineering and Comp Sci Homework Help
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Using Complex Impedances in these RLC Circuit Calculations
Damn so many mistakes. Thx man. I’ll change it and post my next try- NaS4
- Post #19
- Forum: Engineering and Comp Sci Homework Help
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Using Complex Impedances in these RLC Circuit Calculations
Ahh yes I see it- NaS4
- Post #18
- Forum: Engineering and Comp Sci Homework Help
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Using Complex Impedances in these RLC Circuit Calculations
Is this correct?- NaS4
- Post #15
- Forum: Engineering and Comp Sci Homework Help
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Using Complex Impedances in these RLC Circuit Calculations
Yeah i get that. But the formula i got is not the same as the one you are using- NaS4
- Post #12
- Forum: Engineering and Comp Sci Homework Help
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Using Complex Impedances in these RLC Circuit Calculations
And in series it’s Z(total) = Z(1) + Z(2)- NaS4
- Post #9
- Forum: Engineering and Comp Sci Homework Help
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Using Complex Impedances in these RLC Circuit Calculations
1/Z_{total} = 1/Z_{1} + 1/Z{2} in parallel- NaS4
- Post #7
- Forum: Engineering and Comp Sci Homework Help