Recent content by nat1

oops, my fault! i would do the integral of \frac{1}{area between the curves}∫(y1+y2)/2dx is this right? assuming M and dm are the same as above.

im still not sure i understand %100: So each dm will have a vertical center of (y1-y2)/2 and this is where the center of mass for each strip lies. so then i would just need to take the average of these over the interval [0, a] Thanks!

Homework Statement I have equations that are y1= 2sin(\frac{3}{2}x) and y2= \frac{1}{3}x the point where they intersect is called "a" (about x≈1.88). Find the center of mass where M is the total mass of the object.Homework Equations xcm= \frac{1}{M}∫x dM The Attempt at a Solution I found...