Recent content by @navin

If not considering resistive forces, the acceleration is zero. But if we do consider them, then they are always opposing the motion of the car. To keep the velocity of the car constant, the engine has to be kept running, else resistive forces slow u down to rest. So, a force is applied by the...

To me, the sentence seems to be correct and clear. The explanation might be so - If an object A, say, is spinning clockwise then it has some angular momentum about the axis of rotation. It will be given by, L= Iw, where I is moment of inertia and w is the angular velocity. If a piece breaks off...

What you are doing is that when you increase the force on your calculator, the forces are unbalanced. So the calculator accelerates. And then, all of a sudden, you decrease the force you are applying to 5N (which is the kinetic friction) and it, in turn, makes the net force on the calculator...

You can't use dg = v^2(sin∆) here as this is equation gives us the maximum range of the projectile.

OK. From where is the hose 6D away? From the centre of the tank? Or from where the tank begins?