Recent content by Neerolyte

An elevator cable breaks when a 920kg elevator is 28 m above a huge spring (k=2.2 x10^5 N/m) at the bottom of the shaft. Calculate a) the work done by gravity on the elevator before it hits the spring b) the speed of the elevator just before striking the spring and c) the amount of...

hm...Okay..i think this problem should be solve by components, but can i have some hints on how to use component methods?

I'm not really sure what you mean by that, could you explain it again thanks

Can't seem to get this right M1 = 7.0kg M2 = 4.5kg M3 = Mtotal - (M1+M2) Isn't it simply adding up momentum vector of M1, and momentum vector of M2 then the resultant will be momentum of M3? If so, then you get a right angle triangle. You know momentum of both sides and just...

OH my goodness! Thank you so much! and by the way the wording of the question is SOOO bad, because when i enter 1496.693 it says I'm wrong, because the question is referring to the range from the initial firing position. While the question is misleading to us thinking that it's just the range...

Just calulating the range of Fragment 2, i still got the wrong answer. (by the way it's an electronic questionaire that tells you if you get the answer right or wrong if you submit the answer). And i checked all the numbers many many times. I don't know if this is allowed but could...

I have no idea how i keep getting the wrong answer. Here's what i did At the top of the trajectory the horizontal velocity is the same which is cos(35)(125). By using conservation of momentum i can find the velocity of fragment 2 MVix = MVfx (28)(cos(35)(125)) = (14)(0) + (14)(Vf2x)...

hm...basically i need help for the whole question i have no idea how to even start the question

Suppose you throw a stone straight up with an initial velocity of 10.5 m/s and, 1.0 s later you throw a second stone straight up with the same initial velocity. The first stone going down will meet the second stone going up. At what height above the point of release do the two stones meet?

yep got it ^_^ thank you very much

hm...this is what i think of it Since there is strings involved, there must be tension. And since there are 2 strings connected to 1 point holding the 2 spheres. There must be T1 and T2. T1 and T2 must have components. We knew the mass of the two spheres so we know what Fg is, which equals to...

two small spheres, each with 0.120g, have equal charges placed on them. Each sphere is suspended from the same point by its own silk fibre which are 75.0cm long. The repulsive force between them keep their centres 10.0cm apart. What is the charge on each sphere?

i have a couple questions to ask 1: When a satellite is in eclipsical orbit, the total energy should stay the same wether it is at Perigee or Apogee, neglicting friction, correct? 2: Which is larger - The total energy of the 2.00kg satellite in its 160km orbit or the total energy is its...