Recent content by nejikun

I finally sovled it :D thank you veeery much tiny-tim for all your time ;)

it's m(2)*6+ 600 = [m(2)+ 60]*4 and when i solve for m(2) it comes out negative

i tried this : m(2)*V(1)+600=[m(2)+m(L)]*V(2) but it is not correct.

yes g=10m/s^2. So the change is velocity is 10m/s and the mass is 60 kg so the change in momentum is 600 kg*m/s

i think it is 120 kg*m/s

sorry to disturb you again but i still can't solve this. i can't figure out anything

oh so all the problem was because i didn't take into consideration the direction.

Well you confused me even more with the hint :S. I read again all the theory about momentum but i am still missing something. I don't understand what you mean by the load losing momentum.

i thought that it should be : [m(1)+m(l)]*V(1) + m(2)*V(1)= m(1)*V + [m(2)+m(l)]*V(2) the only problem is that i don't know the speed of the first boat after moving the load. the other ways are logically wrong as i now understand. I have no clue for any other way to solve it.

Homework Statement Two boats move parallel each other inertially in opposite directions. They both have a speed of 6m/s. When they are near we move a load from one boat to the other. After this the second boat continues in the same direction with a speed of 4m/s. Find the mass of the second...