ohhh really?
sooo
for f((3*Pi)/2) = -1
and
f(Pi/2) = 3
but why all
that
why I take the values from the derivative and substitute them in the original equation?
So if I substitute x by 0 I am going to find the point where the slope of the tangent line is 0 ?
But I am going to find only one y for each x so how am I suppose to find more than one zero slope if there is?
Actually
I got lost again because I found the derivative
but How am I suppose to find the equation of the tangent line when I do not have a certain point.
Do I need it actually?
I mean some point?
So if I substitute x by 0 I am going to find the point where the slope of the tangent line...
Ok
I am sorry there was something wrong and I could not open the page yestarday.
I guess I should find the derivative of the f(x) which means I should find f'(x) and after
the equation of the tangent line . right?
And i guess the slope is horizontal when the f(x) of the slope equals ohhh...
Homework Statement
Find all points on the graph of the function at which the tangent line is horizontal.
f(x) = 2sinx + (sinx)^2
Homework Equations
Hi guys I have an issue. I do not know how to approach this problem.
I know the chain rule but I still do not know how to solve the...
Homework Statement
Find the limit
lim x\rightarrow1 (4+x-3(x^3) = 2
find the values of \delta that correspond to \epsilon=1 and
\epsilon = 0.1
Homework Equations
The Attempt at a Solution
As much as I know I should do like this.
|(4 + x - 3(x^3)) - 2| < 1...