Recent content by Nerdlight

  1. N

    A lamb grows with its mass proportional

    Lol gotcha, subscripts were throwing me, got to remember that m=kx^3 can take any x value whether its initial/final/middle. Thanks
  2. N

    A lamb grows with its mass proportional

    It was a little confusing ill try to make it more clear. Need to find the value of m at the end of this process. m = kx3 length change by 15.8% xi+.158xi = xf xf = 1.158xi mass increase of 17.3kg mf = mi+17.3 mf = kxf3 mf = k(1.158xi)3 mf = 1.55kxi3 The solutions manual does something here...
  3. N

    A lamb grows with its mass proportional

    A lamb grows with its mass proportional to the cube of its length. When the lambs length changes by 15.8% its mass increases by 17.3kg. Find the final mass. Really stumped thanks for any help mf=kxf3 length change by 15.8% xi+.158xi=xf xf=1.158xi mf=k(1.158x)3 mf=1.55kx3 I...