Recent content by NEUhusky
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Perpendicular Vector with given magnitude
Ugh, still a bit confused. Multiples to get 14 would be either 2 & 7 or 1 & 14. I'm not sure how that applies. Doesn't the magnitude ( √(a2 + b2) ) have to equal 14?- NEUhusky
- Post #5
- Forum: Introductory Physics Homework Help
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Perpendicular Vector with given magnitude
Thanks! Glad I found this place! :smile: Hm, well the magnitude of the given vector A is √(8^2+5^2) which is approximately 9.43. Using the dot product I know that the perpendicular lines are either B = -5i-8j or 5i+8j because the dot product equals zero. Unfortunately the magnitude is...- NEUhusky
- Post #3
- Forum: Introductory Physics Homework Help
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Perpendicular Vector with given magnitude
Homework Statement Given a vector A = 8i − 5j, find the vectors in the xy plane that are perpendicular to A and have a magnitude of 14. The Attempt at a Solution I can find the vector perpendicular to A quite easily. I'm having trouble finding the perpendicular line when it has the...- NEUhusky
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- Magnitude Perpendicular Perpendicular vector Vector
- Replies: 5
- Forum: Introductory Physics Homework Help
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Velocity needed to launch a car
True. Thanks for the reply. I guess the movie effects are just playing tricks on my eye. The kicker will have to be the force required to break a concrete barrier and sustain the velocity needed to make the jump.- NEUhusky
- Post #3
- Forum: Introductory Physics Homework Help
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Velocity needed to launch a car
Homework Statement Hi all, this is my first post here because I am having an issue with an assignment in my General Engineering class (physics related). The assignment is to find an action movie clip that portrays something to be real but is, in reality, not possible. My group and I decided on...- NEUhusky
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- Car Launch Velocity
- Replies: 2
- Forum: Introductory Physics Homework Help