Recent content by niallj

The degree of interaction between two orbitals is related to how much they overlap with each other. Two orbitals which are of similar energies overlap much more than two of very different energies. I don't remeber much about rates, I'm afraid, but I assume that if you have a very large...

That's right- remember that \Delta G = \Delta H - T \Delta S. So it get's canceled when you multiply entropy by temperature.

CV is J :)

You can work that out by looking at the units on the left hand side. The units of 2F\frac{dE}{dT} are C mol^{-1} V K^-1. Can you simplify that a bit to get the more standard unit?

Yes, that's another way of doing it :)

You need to solve the following equation: \Delta G = \Delta H - T \Delta S. You know \Delta G and T, which leaves two unknowns: \Delta H and \Delta S. You cannot solve for two unknowns with a single equation: you need to have two sets of values. The way to do this is to solve the following...

E (and, therefore, \Delta G) depends on temperature. So work out \Delta G at some different temperatures, and you can solve the equation to get \Delta H and \Delta S

Because there are two unknowns, \Delta H and \Delta S, you need more than one value of \Delta G (at least two), to get the solution. \Delta G = nFE, so you need to work out \Delta G over a range of values of E. Now, what does E depend on?

If you know E, then you can calculate \Delta G, as you have done already. You also know that \Delta G = \Delta H - T \Delta S. But, this leaves you with two unknowns. Perhaps you can calculate some more values of \Delta G, and then solve for \Delta H and \Delta S? Hint: they've given you a...

The wikipedia page seems to offer quite a good explanation of what's going on: http://en.wikipedia.org/wiki/Optical_activity#Theory I'm not sure what your level of current knowledge is, so if you have any trouble understanding that I'll be happy to explain it as best I can :)