many thanks that really helps me. so I would then use the formula shear stress= load/area? so in that case mild steel has a shear strength of 80kN/mm2. So the load required to strip the thread would be 80,000=load/(4xL) where L is length of the nut?
the object of the report is to prove that...
Hi all,
im building a bench vice for college and I need to do a report on It also. the problem I am having is working out the force required to strip the threads off an M10 x 1.5 metric thread. both the thread and nut are to be made from mild steel. any info that I could find online has only...
forces up = forces down forces left = forces right
Rn + 300sin(theta) = mg F = 300cos(theta)
Rn + 300sin(theta) = 500.31 muRn = 300cos(theta) because F = muRn
Rn = 300cos(theta)/mu...
Homework Statement
im having problems with this question...a body weighing 51kg is pulled on a horrizontal plane with coefficient of friction 0.3. a force of 300N is applied at angle x ... find the angle x?
Homework Equations
The Attempt at a Solution
the only solution i hav come...