Recent content by Nick P

What I have right now... is that Syp,SS304=206.8MPa F=π(.075m)2*206.8E6 = 3.66MN and relating that to the current thickness we have at 5cm σ=\frac{3.66MN}{.15m*.05m}=488MPa And 488MPa < Sut,SS304 with Sut,SS304=517.02MPa But I'm pretty positive I'm making some logical error here.

0.7512 meters

Designing a cylinder using Stainless Steel 304 and am trying to figure out the minimum thickness of the outer wall of the cylinder to avoid being puncture by a 6in diameter steel bar after falling 1 meter onto the bar. Cylinder will weigh approximately 5500kg.