Thickness of 304 stainless sheet to avoid puncture

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The discussion focuses on determining the minimum thickness of a 304 stainless steel cylinder to prevent puncture from a 6-inch diameter steel bar dropped from a height of 1 meter. The cylinder's weight is approximately 5500 kg, with an outer diameter of 0.7512 meters. Calculations indicate that the force exerted on the cylinder is 3.66 MN, leading to a stress of 488 MPa, which is below the ultimate tensile strength of 517.02 MPa for stainless steel 304. The original poster expresses uncertainty about their calculations and suspects a logical error. Clarifying the thickness requirement is essential for ensuring structural integrity under impact.
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Designing a cylinder using Stainless Steel 304 and am trying to figure out the minimum thickness of the outer wall of the cylinder to avoid being puncture by a 6in diameter steel bar after falling 1 meter onto the bar.

Cylinder will weigh approximately 5500kg.
 
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What is the outer diameter of the cylinder?
 
0.7512 meters
 
What I have right now... is that

Syp,SS304=206.8MPa

F=π(.075m)2*206.8E6 = 3.66MN

and relating that to the current thickness we have at 5cm

σ=\frac{3.66MN}{.15m*.05m}=488MPa

And 488MPa < Sut,SS304 with Sut,SS304=517.02MPa

But I'm pretty positive I'm making some logical error here.
 
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