Recent content by Nimlidor

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    Product of a third- and second-order tensor.

    Does contracting over two indices mean that you make a sum of nine products? B_{i11}C_{11}+B_{i12}C_{12}+B_{i13}C_{13}+...+B_{i32}C_{32}+B_{i33}C_{33}
  2. N

    Product of a third- and second-order tensor.

    So if I understand this correctly, in order to get "i-th" component of a vector you have to take i-th "slice" of third-order tensor and multiply it with second order tensor: not in the standard way we multiply matrices, but rather just multiply j,k-th component of both tensors and sum over all...
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    Product of a third- and second-order tensor.

    Hi, I have read that vector of polarisation \vec{P} and stress tensor T are linked with equation \vec{P}=\underline{\underline{d}} \: \underline{T} where d is a third-order piezoelectric tensor. Can anyone explain how you multiply a third and a second-order tensor to get a vector? A good link...
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