Recent content by njcc7d

fair enough. thank you for answering my question, though that makes the problem a little more complicated... i hate it when that happens.

if Y is an eigenstate of both A and B with respective eigenvalues a and b and respective adjoints (A+) and (B+), <Y|AB|Y> = <Y|BA|Y> = <Y|Ab|Y> = <(B+)Y|A|Y> = b<Y|A|Y> = (b*)<Y|A|Y> Therefore, b=(b*), and so it follows that B=(B+), or B is Hermitian.

Homework Statement If A is a Hermitian operator, and [A,B]=0, must B necessarily be Hermitian as well? Homework Equations The Attempt at a Solution