Recent content by nomather1471

Sorry but i can't understand anything with physics notation, i think Lorentz metric be a non-degenerate because of the definition of degenere metric...I mean subspaces by subset of Lorentz space, timelike subspaces are space which has a non-degenerate metric on it and lightlike subspace are...

Thanks, i agree with you, these questions are from the Rafael Lopez Minkowski Lectures, about question 3 the author able to think the unit vectors, the original is E2+E3 is null so if we take E2=(0,1,0) and E3=(0,0,1) then E2+E3=(0,1,1) which is a null vector, here the signature is (+,+,-) in E13...

Can he talk about hyperboloid which is embedded in Minkowski, because hyperboloids can be thought as a sphere of imaginary radius...

Hi there, i have a lot of question about Lorentz-Minkowski geometry: 1) Is Lorentz metric degenere or non-degenere? Why? 2) In spacelike subspaces only spacelike vectors live in it there is not problem here but how can we say that timelike subspaces include null and spacelike vectors...

I am student at geometry so your notation is quite different for me but thanks for everyone for all replies...

I think you have to show that: (X^1 Y^1)^2 \leq ((X^2)^2 + (X^3)^2 + (X^4)^2)((Y^2)^2 + (Y^3)^2 + (Y^4)^2)

[SIZE="4"]Can we show orthogonality of timelike and null vector?

That's conjecture is Ramanujan's problem and the problem haven't solved from anybody yet, i haven't too :)

Is there any problem at my proof?

you are true i will turn again...

http://www.hizliupload.com//viewer.php?id=475631.jpg

it is important point of exponential of 4 is congruence 4 or 6 mod 10, i have missed it i think :)

(3,5)=1 so 3 and 5 coprime then 3x+5y=1, x=2, y=-1 then 3.2+5(-1)=1 2(3.2+5(-1))=2-->3.(4)+5.(-2)=2 3(3.2+5(-1))=3-->3.(6)+5.(-3)=3 4(3.2+5(-1))=4-->3.(8)+5.(-4)=4 . . ...

if x^6 is not element Q x is not element Q too, you can see it...So it is a contradiction and x is irrational.

http://www.loadtr.com/465889-aasasasasasas.htm