Recent content by noodle951

So the force required "F ??" Is taken from the the sum of the X components and the sum of the Y components for the container and linkage fixing pin?

Ah that makes more sense. How would I go about finding the X and Y components at the lower ground fixing pin? Would I find the force going along the lower angled beam (hypotenuse) and go from there? Also, once I've found the X and Y components, how do I go about finding the force required "F...

Something like this?

The horizontal component of F1? at either end of the beam? Then the vertical at the end of the first angled beam?

This better? Not sure what other forces I need.

This ok?

Alright, handy to know! :) So if i change the 4 deg angle to 25, I get: 9/(sin(25)) = 21.3KN on the upper angled beam.

Hi Nidum, does this explain it better? The long horizontal beam represents an actuator. The mechanism is to tip a container.

Homework Statement Hi, please see the attached file. I am trying to find the force as illustrated in the diagram. Homework Equations [/B] The Attempt at a Solution I've found the force for the 4deg beam and therefore the horizontal beam however I am unsure how to take into account the...