Recent content by Normalization

Hey guys, I was messing around with my guitar (classical guitar) and my amp lately. I put the treble on lowest, bass highest, reverb highest, mid highest and mid frequency lowest. When I pluck a string when my guitar is close to the amp, the amplified sound from my amp causes that string to...

Awesome, thanks :P

Are you sure it's not I1 = R2 / (R1 + R2) IT? Because: I1 = VP/R1 Where VP is the potential difference across the parallel part. And VP = IT × 1/(1/R1+1/R2) And 1/(1/R1+1/R2) = 1/(R1+R2/R1×R2) = (R1×R2/R1+R2). So VP = IT × (R1×R2/R1+R2) So I1 = IT × (R1×R2/R1+R2) × 1/R1 = IT ×...

BTW: If you have 2 resistors in parallel (R1 and R2), do you just find the current going through one resistor R1 by doing R1/(R1 + R2) × ITotal?

yee :D

Before: RTotal = 3R/2 Because of R + 1/(1/R + 1/R) = R + R/2 = 3R/2 So ITotal = V/(3R/2) = 2V/3R IL = ITotal/2 (identical lamps) = 2V/6R = V/3R IN = ITotal = 2V/3R After: RTotal = 2R Because RTotal = R1+R2 = R+R = 2R So ITotal = V/2R IL = IN = ITotal = V/2R V/2R < 2V/3R So IN...

Thanks a lot guys that really helps! I meant V^2/P sorry not P/I^2 (typo). And yes the current stays constant throughout the whole circuit (after removal of parallel light bulb) and increases relative to L and decreases relative to N.

Homework Statement I've done both these questions with correct answers, but I just want sure that I chose the right choices for the right reasons. The questions are: Homework Equations V = IR P = I2R P = V2/R The Attempt at a Solution The answers for both are D. The reason...

Ok thank you, just wanted to make sure that an upwards resultant force results in an increase apparent weight because of N3.

Thank you chet and technition, but is this right though?

Hmm... Still not quite satisfied. So suppose instead of a mass I have a mass on a spring. The spring will extend more as there is an upwards acceleration right? Because the apparent weight then is larger than the weight at equilibrium. So is it the increased push on the retort stand and spring...

ƩF = N - W Where N is the normal force. So N - W = Ma So N (apparent weight) = Ma + Mg so N = M(a+g) But why is N the apparent weight? Is it because of Newtons third law?

Homework Statement The numbers aren't important because I'm after getting a more intuitive sense of the problem. When an elevator is accelerating upwards with a mass in it on a scale. Why is the apparent weight the normal force? Homework Equations F=ma W=mg The Attempt at a...

Cool, thanks :D

Oh I see :) Because the phase factor is independent of x it acts as a constant on ψ so taking the derivative of one of the ψ's wouldn't affect the value of the phase factor, but if it was dependent of x one would need to use the product rule to take the partial of one of the psi's.