Recent content by nothingislost

No responses :( Help. When i go further i get that \omega^2=(g/a)(\cos\theta - 2)

ok so these are my two equations of motion mg\cos\theta + ma\dot\theta^2=\lambda and ma^2\ddot\theta + mga\sin\theta = 0 plus the equations of constraint that r=a. then what i was doing was setting lambda to zero to find where the tensions force goes to zero for slack...

Ok. So my lagrangian is L = \frac{1}{2}m(\dot r^2 + r^2 \dot \theta ^2 ) + mgr\cos (\theta ) with the constraint that r=a or f=r-a from this i can get the equations of motion for \theta and \omega next i solve for the lagrangian multiplier and get \lambda for the r equation...

A mass hangs on a string and is struck by a horizontal impulsive force that introduces an angular velocity w, using a lagrangian multiplier what are the conditions that causes the string to go slack. the constraint is simply that the string is of constant length and therefore the radius of...

:smile:

ok i see and the total force necessary would just be the tangential and the centripetal forces, basically somewhere between those two vectors right?

A carousel going counter clockwise starts from rest and accelerates at a constant angular acceleration of 0.02 rev/s^2. A girl sitting on a bench on the platform 7 m from the center is holding a 3kg ball. Calculate the magnitude and the direction of the force she must exert to hold the ball 6s...

so was the constraint that r is constant? How does the impulse force enter the equation?