Mass on a string struck by an impulsive force

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Homework Help Overview

The discussion revolves around a mass hanging from a string that is subjected to a horizontal impulsive force, leading to the introduction of angular velocity. Participants are exploring the conditions under which the string goes slack, particularly focusing on the implications of using Lagrangian mechanics and the nature of the string as a constraint.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to derive the conditions for the string going slack using Lagrangian multipliers and equations of motion. Questions are raised about the validity of the derived condition for angular velocity and how to properly account for the string's properties compared to a solid rod.

Discussion Status

Some participants are providing insights into the calculations and equations involved, while others are questioning the assumptions made regarding the nature of the string and the implications of the derived conditions. There is an ongoing exploration of the relationship between angular velocity and the slack condition.

Contextual Notes

Participants note the constraint of the string being of constant length and express uncertainty about how this affects the dynamics compared to a solid rod. There is also mention of the need for further calculations to clarify the situation.

nothingislost
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A mass hangs on a string and is struck by a horizontal impulsive force that introduces an angular velocity w, using a lagrangian multiplier what are the conditions that causes the string to go slack.

the constraint is simply that the string is of constant length and therefore the radius of motion is of constant distance, r=a. I write the lagrangian equations for r and theta and then solve for the constraint force/multiplier. for the string to go slack the constraint force in r goes to zero and therefore lambda goes to zero.

solving for theta dot or omega i get that the condition for a slack string is that w=sqrt (g/a)

This doesn't make sense however as this is the condition when theta is at 180 and by logical reasoning i know that the string starts to go slack when theta max is just over the horizontal or 90.

What am i doing wrong here and how do i account for the fact that this is a string and not a solid rod?

thanks :)
 
Last edited:
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Hi nothingislost! :wink:

(have a square-root: √ and an omega: ω and a theta: θ :wink:)
nothingislost said:
What am i doing wrong here and how do i account for the fact that this is a string and not a solid rod?

This is the same problem as a mass moving on the inside of a sphere … the string going slack corresponds to the object losing contact with the sphere.

But if you want us to check what went wrong, you'll need to show us your full calculations. :smile:
 
Ok. So my lagrangian is

[tex]L = \frac{1}{2}m(\dot r^2 + r^2 \dot \theta ^2 ) + mgr\cos (\theta )[/tex]

with the constraint that r=a or f=r-a

from this i can get the equations of motion for [tex]\theta[/tex] and [tex]\omega[/tex]

next i solve for the lagrangian multiplier and get [tex]\lambda[/tex] for the r equation.

but i feel that i have not accounted for the fact that this is a string and not a solid rod with my constraint. how can i account for this?

I end up solving for the slack condition where the constraint for on r goes to zero and get

[tex]\omega=\sqrt (g/a)[/tex]

and i know this ofcourse can't be true for a string. what am i missing?
 
You solved for [tex]\omega[/tex]? It is given in the problem. Remember, [tex]\omega[/tex] could be so high that it results in the mass fully rotating around the center without going slack.
 
ok so these are my two equations of motion

[tex]mg\cos\theta + ma\dot\theta^2=\lambda[/tex]

and

[tex]ma^2\ddot\theta + mga\sin\theta = 0[/tex]

plus the equations of constraint that r=a.

then what i was doing was setting lambda to zero to find where the tensions force goes to zero for slack situation. is this the right direction?
 
Last edited:
No responses :( Help.

When i go further i get that [tex]\omega^2=(g/a)(\cos\theta - 2)[/tex]
 

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