Recent content by nuclearrape66

so are you saying that there can be an infinite amount of forces acting on an object sp that it's at equilibrium?

Homework Statement how mnay forces can you add to kep an object in equilibrium Homework Equations The Attempt at a Solution is it infinite? and what would be the reason? It doesn't seem realistically possible??

oh i see, so so then if you do the absolute value thing, where you take the limit of any alternating sequeence and if that diverges then the alt sequence diverges if it converges then the sequence converges. does that work all the time for these?

so for (-1)^n(1/n) i would do: lim (-1)^2n(1/2n) = 0 and lim (-1)^2n+1(1/2n + 1 ) = 0 and therefore it's 0. but what about (-1)^n(n/n+2)

so youre saying to plug in 2n for n and get its limit... then plug in 2n + 1 for n and find its limit... and if they both go towards the same thing then it converges to that number?

If I'm taking the limit of a sequence of numbers that is {An} and An alternats in signs. am i suppose to take the absolute value to determine the limit. and if the absolute value of An diverges then the lmit diverges? or how am i suupose to take the limit of alternating signs?

and therefore by the divergence test...the series diverges?

if you can hint me to what test i should use maybe i can figure it out.

i've tried the root test. does not work. meaning it's inconclusive. and i don't understand your question. "Does the argument of the series goes to 0 as n increases without bounds?" are you saying do the terms get closer to zero? yes.

does the series from 1 to infinity of \sum(1 - (2/n))^3n convegre or diverge. i've tried almost all the tests and can't figure it out...

stop whoring my thread, if you don't like it, then don't bother to click on my thread and waste your time...

no youre not allowed. add the functions together and differentiate it with respect to whatever subscipt it is

private messaging has nothign to do with forum posting...understand these rules...

are you going to go through my inbox? and what you're doing right there is whoring my thread...if you don't wanan help don't help. dotn speak for everyone, speak for yourself.

oh okay...ratio test. now i see