Does the Series $\sum (1 - \frac{2}{n})^3n$ Converge or Diverge?

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Homework Help Overview

The discussion revolves around the convergence or divergence of the series \(\sum (1 - \frac{2}{n})^3n\). Participants are exploring various tests and approaches to determine the behavior of the series as \(n\) approaches infinity.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants have attempted several convergence tests, including the root test, and are questioning the implications of the terms approaching zero. There is also a reference to a known limit involving \(e\) that may relate to the series.

Discussion Status

The discussion is ongoing, with participants sharing their attempts and questioning the validity of their approaches. Some guidance has been offered regarding the behavior of the terms in the series, but no consensus has been reached on the convergence or divergence of the series.

Contextual Notes

There is a mention of the divergence test and a hint towards manipulating a known limit to analyze the series further. Participants are also grappling with the implications of the terms not approaching zero in a specific context.

nuclearrape66
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does the series from 1 to infinity of \sum(1 - (2/n))^3n convegre or diverge.

i've tried almost all the tests and can't figure it out...
 
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Have you even tried the simplest test of them all? Does the argument of the series goes to 0 as n increases without bounds?
 
i've tried the root test. does not work. meaning it's inconclusive.

and i don't understand your question.
"Does the argument of the series goes to 0 as n increases without bounds?"
are you saying do the terms get closer to zero? yes.
 
if you can hint me to what test i should use maybe i can figure it out.
 
nuclearrape66 said:
are you saying do the terms get closer to zero? yes.

Yes, this is what I was asking, but 'yes' is not the answer I had in mind!

Remember that

\left(1+\frac{1}{n}\right)^n \rightarrow e

!
 
and therefore by the divergence test...the series diverges?
 
I was merely pointing out a sequence that behaves like the argument of your series and that does not go to 0.

However, you can cleverly manipulate the identity

\left(1+\frac{1}{n}\right)^n \rightarrow e

to find the precise value of the limit you're interested in.
 

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