Recent content by ohhwhat

I got it. You can close this. Thanks to everyone who helped me!

As solution for "u", i got u1=60, u2=20, is that correct?

Thanks! Then i finally understand the issues with fractions, i guess

Idk what it's called in english, its "computer stuff", you know? I don't know why i need to have such a big knowledge about optics, nvm i have to do it anyways

So, the next line is: 80/u(80-u)=1/f , right?

Math courses where i don't need stuff like that anymore. I learned that a few years ago and cannot remember how it works. Also, I am especially very bad at maths, yikes. This "optics problem" is unfortunately part of my apprentice ship, although i have nothing to do with optics there.

Maybe it's 2/a+b?

No, sorry, i don't really understand this

Yeah i had the same idea like you, unfortunately i don't know how to solve that.^ Maybe this: 1/f= 2/80-2u ?

So, u+v=80cm Maybe i can use v=80−u in some way? I struggled half an hour to solve it now, unfortunately, i didn't came to a solution...

Mhm, what should i do with the heigh of the object (6cm)? :/ Also, i have either u or v, so how should i work with the optic equation right now?

So the distance of 80cm is the result of u + v, am i right? Also, the solution we are looking for is u, right?

Unfortunately, there's no formula i know about, so i have no idea how to solve this... Hope you can help me out... Greetings