Ok, so the voltage drops when I finish the circuit with the LED because it can't produce the electrons needed to power the circuit?
What is confusing me is the initial voltage, that should be enough of this "something to push extra electrons" (I mean the voltage is created by charge, so there...
Hi, I was doing some tests with lemon batteries today and found that it produced little current (not enough to light a small LED at least and I serially connected 4 lemons getting above 3V) which is explained in some places in the following way:
2 electrons are produced by the zinc (if your...
Almost the right way to find the acceleration but you are calculating the forces incorrectly.
Ok, here is what you have to do, consider all the forces at play here, there is the gravity force pulling on both the masses but only one of the gravity forces causes the masses to move, the gravity...
Almost the right way to find the acceleration but you are calculating the forces incorrectly.
Ok, here is what you have to do, consider all the forces at play here, there is the gravity force pulling on both the masses but only one of the gravity forces causes the masses to move, the gravity...
You don't show any attempt at a solution, are you completely lost?
What is your first intuition? What forces are at work here? What is the main principal that we should use regarding forces?
You don't show any attempt at a solution, are you completely lost?
What is your first intuition? What forces are at work here? What is the main principal that we should use regarding forces?
Think of centripetal acceleration, the tube is forcing the liquid to turn so the tube must be applying some force on the liquid but do you know how to connect radius, angle, arc, velocity and centripetal acceleration?
That is the well known formula
x = x_0 + v_0*t + 0.5*a*t^2
used in all three parts of the journey.
The first term in my first equation is the last part of this formula, that describes the distance traveled during the first 4 seconds.
The second term in my first equation is the second part of...
That is the well known formula
x = x_0 + v_0*t + 0.5*a*t^2
used in all three parts of the journey.
The first term in my first equation is the last part of this formula, that describes the distance traveled during the first 4 seconds.
The second term in my first equation is the second...
Ok then, what you have to do here is write up 3 terms that all show the distance traveled as a function of a.
The first 4 seconds the distance traveled is 0.5at^2, then you have to add a second term that shows the distance traveled during the next 8 seconds as a function of a and lastly a term...
Ok then, what you have to do here is write up 3 terms that all show the distance traveled as a function of a.
The first 4 seconds the distance traveled is 0.5at^2, then you have to add a second term that shows the distance traveled during the next 8 seconds as a function of a and lastly a...
Ok, that's a start.
But your equation assumes that the whole 144m are traveled in the initial 4 seconds which is not true, the 144 m are traveled in 16 seconds but with varying speed (except between 4 and 12 seconds) so you have to break the distance down into three parts and each part gets its...
Well, we don't usually do the work for the students here but we try to nudge them in the right direction.
The right direction here is how would you write up an equation for the distance traveled as a function of the acceleration a (what is the deceleration as a function of a? can you tell that...