Recent content by omg precal

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    Finding Inverse Exponential Functions: A Method for Solving Without Answers

    that gives me 3^x = 243. using logarithms... x log3 = log 243 x = log 243/ log 3 x = 5 am i correct?
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    Finding Inverse Exponential Functions: A Method for Solving Without Answers

    First of all, sorry for asking so many questions. I do not want answers, just a method of solving them. Homework Statement For the exponential function f(x) = ab^x, suppose f(2) = 2 and f(4) = 18. a. Find a and b. b. Find f^-1(54), the inverse function. Homework Equations None...
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    How to Minimize Cost for an Open-Top Box with Given Volume and Width

    Cost Function = 16l + 16h + 4lh Cost Function (h) = 160/h + 16h + 40 Height = 10 Length = 1 Width = 4 16(10) + 16(1) + 4(1)(10) = 216 dollars 16(100) + 16(0.1) + 4(0.1)(100) = 1641.60 dollars (smaller you go, much bigger the price gets!) 16(5) + 16(2) + 4(5)(2) = 156 dollars...
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    How to Minimize Cost for an Open-Top Box with Given Volume and Width

    This is, by far, the hardest summer assignment I've ever had... But thanks to you guys, I managed. =]
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    How to Minimize Cost for an Open-Top Box with Given Volume and Width

    Wow. I was blinded by stupidity. Thank you! No problem at all. Thanks a lot for helping, though.
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    How to Minimize Cost for an Open-Top Box with Given Volume and Width

    :confused::confused::confused: wouldnt 0 length mean it is 2-dimensional? infinity height... that would be tall :smile: I think I'll just leave it blank. o.O
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    How to Minimize Cost for an Open-Top Box with Given Volume and Width

    and wouldn't that also screw up my domain for H? or would it be all real numbers lol
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    How to Minimize Cost for an Open-Top Box with Given Volume and Width

    yeah... i spent a good hour trying to find some kind of non existent hint in the wording or just simply another solution, but i couldnt. i just hope my teacher made a mistake, i don't want to do bad on it.
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    Who Are You People? Intelligent & Advanced Answers

    yeah... this is one of the best and most useful forums I've ever visited... and the people are nice.
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    Who Are You People? Intelligent & Advanced Answers

    that is awesome. i think I am going to join this forum later in life (if its still alive)
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