Recent content by Ondyman

thank you! :)

Theory says that in real life in band 118 - 136 MHz we would use 8,33 kHz spacing in civil aviation and 25 kHz spacing in military aviation. However, I think this problem is just made up to see if I can use Dopplers formula... However, if I focus only on Doppler part of this problem, the shift...

God... thank you.. quite tired this afternoon... f=f0*((v+v0)/v) where f = ? f0 = 118 000 000 Hz v´ = speed of light = 299 000 000 ms v0 = speed of airplane towards the tower = 2 MACH = 636 ms f = 118 000 270.7 Hz it means that the singal will be shifted by 270.7 Hz.. so all we need is to...

allright, thanks! So if I use a common formula for doppler and set original frequency to 118 MHz, the frequency which tower (or other plane) got is 354 MHz f=f0*((v+v0)/v) where f = ? f0 = 118 MHz v´ = speed of sound = 343 ms v0 = speed of airplane towards the tower = 2 MACH = 636 ms I got the...

I found it confusing since there is only "mutual" speed of both aircrafts and hence I do not know how to correctly put it into the common Dopplers formula...