Recent content by oom kaaspaas

I found the answer to my own question referring to how pi x D x T was derived. The full equation is pi x D x T + pi x T x T and as t is assumed to be small, T xT would be minute. Now only the question if this equation holds for crushing stresses remains and I assume that it will.

Thanks it makes sense, I still have two more questions on the subject namely how was piXDxT derived and can I use the same equation if there were a force tending to crush the cylinder asuming the t is reasonably smaller than d

Thanks for your timely response and sorry for not spesifying. p is the atmospheric pressure,d is the inside diameter(thus excluding the thickness of the cylinder wall) and t is the thickness of the before mentioned wall. It is a valid point that as this is a thin cylinder the circumference...

the method used is the force projected on the circumference instead of the cross sectional area. From what I can gather this is wrong as the stress involved is Force dived by the cross sectional area.

In Rc Stephen's book Strength op materials, the longitudinal stress in a cylinder(see) attachment caputure.jpeg. My question is how is the area(pi X d X t ) is derived as my calculations show that this area should equate to (pi x d x t + t x t)