Thx for the help. I can see how a= 4d- (3/2)c and b= c+ d, but why do u choose d=1 c=0 at first, and the d=0 and c=2. And how is The Null space of B is given by <a, b, c, d> with 2a- 3b+ 6c- 5d= 0 and -b+ c+ d= 0. I can't seem to figure this part out, but i understand the answer to part two...